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  • Stuck here, help me understand: An unknown metal of mass 192 g heated to a temperature of 1000 C was immersed into a brass calorimeter of mass 128 g containing 240 g of water at a temperature of 8.40C. Calculated the specific heat of the unknown metal if

An unknown metal of mass 192 g heated to a temperature of 1000 C was immersed into a brass calorimeter of mass 128 g containing 240 g of water at a temperature of 8.40C. Calculated the specific heat of the unknown metal if water temperature stablizies at 21.50 C.

(Specific heat of brass is 394 J Kg-1 K-1)

 

  • Option 1)

    458 \: J \: kg^{-1}K^{-1}

  • Option 2)

    1232 \: J \: kg^{-1}K^{-1}

  • Option 3)

    654 \: J \: kg^{-1}K^{-1}

  • Option 4)

    916 \: J \: kg^{-1}K^{-1}

Answers (1)

best_answer

 

Calorimetry -

Heat lost = Heat gained

- wherein

Represents the law of conservation of energy

 

 

Mixture of two substance -

\theta_{mix}=\frac{m_{1}c_{1}\theta_{1}+m_{2}c_{2}\theta_{2}}{m_{1}c_{1}+m_{2}c_{2}}

- wherein

\theta_{min}= Temperaure of mixture at equilibrium. 

192 \times s\left ( 100 - 21.5 \right ) = 128\times 394(21.5-8.4)+240\times 4200(21.5-8.4)

s = 916Jkg^{-1}K^{-1}

 


Option 1)

458 \: J \: kg^{-1}K^{-1}

Option 2)

1232 \: J \: kg^{-1}K^{-1}

Option 3)

654 \: J \: kg^{-1}K^{-1}

Option 4)

916 \: J \: kg^{-1}K^{-1}
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