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Truth table for the following digital circuit will be :

  • Option 1)

  • Option 2)

  • Option 3)

  • Option 4)

 

Answers (2)

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As we learnt

AND Gate -

Y= A\cdot B

- wherein

A and B are input

Y is out put

 

 

 

NAND gate -

NOT + AND gate

- wherein

Y= \overline{A\cdot B}

A and B are input

Y is out put

 

 

z=\overline{xy.\overline{x}y}=\overline{xy}+\overline{\overline{x}y}

 

 


Option 1)

Option 2)

Option 3)

Option 4)

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