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The type of hybridisation and number of lone pair (s) of electtrons ofXe \: \: \: in \: \: XeOF_{4} respectively , are :

  • Option 1)

    sp^{3}d^{2}\: \: and \: 1

  • Option 2)

    sp^{3}d\: \: and \: 2

     

  • Option 3)

    sp^{3}d^{2}\: \: and \: 2

  • Option 4)

     

    sp^{3}d\: \: and \: 1

Answers (1)

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Hybridisation -

The process of mixing of atomic orbitals belonging to the same atoms of slightly different energies so that a redistribution of energy takes place between them  resulting in the formation of new set of orbital of equivalent energies and shape is called hybridisation.

- wherein

The new orbitals thus formed are called hybrid orbitals

 

 

 

 

VSEPR Theory -

 

1.  The shape of the molecule is determined by repulsions between all of the electron pair present in valence shell.

2.  Order of repulsion 

             lone \:pair-Lone\: pair> Lone\:pair-Bond\:pair> Bond\:pair-bond\:pair

3  Repulsion among the bond pair is directly proportional to the bond  order and electronegativity difference between the central atom and the other atom.

-

 

 

Determination of shape of molecules using VSEPR Theory -

VSEPR Rules:

1. Identify the central atom

2. Count its valence electrons

3. Add one electron for each bonding atom

4. Add or subtract electrons for charge  

5. Divide the total of these by 2 to find the total number of electron pairs

6. Use this number to predict the shape

 

 

- wherein

Image result for vsepr theory

 

As we have learnt in Hybridisation:

sp^{3}d^{2}

  5 \sigma bond

1 \pi bond


Option 1)

sp^{3}d^{2}\: \: and \: 1

Option 2)

sp^{3}d\: \: and \: 2

 

Option 3)

sp^{3}d^{2}\: \: and \: 2

Option 4)

 

sp^{3}d\: \: and \: 1

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