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Get Answers to all your Questions
- Home
- Engineering
- The amount of anhydrous Na_{2}CO_{3} present in 250 ml of 0.25 M solution is
A.
6.225 G
B.
66.25 G
C.
6.0 G
D.
6.625 G
Answers (1)
0.25M solution contains 0.25 moles in 1 litre (1000 ml)
250 ml of the solution will contain = 250/1000 x 0.25 = 0.0625 moles
Molar mass of Na2CO3
= 23x2 + 12 + 16x3
= 106 g/mol
Mass = Number of moles x molar mass
Mass of Na2CO3 = 0.0625 x 106
= 6.625 g
Read more on Brainly.in - https://brainly.in/question/4096459#readmore
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