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  • The area of cross section of the two arms of a hydraulic press is  1 cm2 and 20 cm2 respectively. A force of 10 N is applied on the water in the thinner

The area of cross section of the two arms of a hydraulic press is  1 cm2 and 20 cm2 respectively. A force of 10 N is applied on the
water in the thinner arm. What force (in N) should be applied on the water in the thicker arms so that the water may remain in equilibrium?

Option: 1 300

Option: 2 200

Option: 3 400

Option: 4 500

Answers (1)

best_answer

 

 

 

In equilibrium, the pressures at the two surfaces should be equal as they lie in the same horizontal level. If the atmospheric pressure Po is  and a force F is applied to maintain the equilibrium, the pressure just below the pistons are

   P_{M}=P_{0}+\frac{10 \mathrm{N}}{1 \mathrm{cm}^{2}} \text { and } P_{N}=P_{0}+\frac{F}{20 \mathrm{cm}^{2}}

These pressure should be same, PM = PN 

So, F = 200 N

Posted by

jitender.kumar

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