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IMG_20190124_233406.jpg EXANII'LE 21 The Of deviation a, a + d, a + 21, a + (2n 1) d, a + 2nd about the tncan is (a) Ans. (b) (b) (c) SOLUTION The mean of the given series is a + nd. (See chapter 52). Mean deviation about mean 1 I (a + rd) (a + nd) I (211 + 1) 2n d n 11 (11 + 1) x 2 211 + 1

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best_answer @Shyam Both of the summation terms will be equal as | r - n | gives same values in interval [1,n] & [n,2n] so you can write the summation as double of summation from 1 to n.
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Anurag Uikey

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