IMG_20190124_233406.jpg EXANII'LE 21 The
Of
deviation
a, a + d, a + 21,
a + (2n 1) d, a + 2nd about the tncan is
(a)
Ans. (b)
(b)
(c)
SOLUTION The mean of the given series is a + nd. (See
chapter 52).
Mean deviation about mean
1
I (a + rd) (a + nd) I
(211 + 1)
2n
d
n
11 (11 + 1)
x
2
211 + 1
Answers (1)
@Shyam Both of the summation terms will be equal as | r - n | gives same values in interval [1,n] & [n,2n] so you can write the summation as double of summation from 1 to n.