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Two spherical condutors A and B of radii 1mm and 2mm are seperated by a distance of 5cm and are uniformly charged. If the spheres are connected by a conducting wire then in equilibrium condition ,the ratio of the magnitude of electric fields at the surface of spheres A and B is..?

Answers (1)

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@Swapnil Rajput

Two spherical condutors A and B of radii 1mm and 2mm are seperated by a distance of 5cm and are uniformly charged. If the spheres are connected by a conducting wire then in equilibrium condition ,the ratio of the magnitude of electric fields at the surface of spheres A and B is..?

Answer:

If we cannect two spherical conductors by a conducting wire then the potential of both A and B will be the same,

So,  V=Er

\\\frac{V_A}{V_B}=\frac{E_A\times r_A}{E_B\times r_B} \\\\\because V_1=V_2 \\\\\frac{E_A}{E_B}=\frac{r_B}{r_A} \\\\\frac{E_A}{E_B}=\frac{2}{1}

So,

the ratio otf the magnitude of electric fields at the surface of spheres A and B will be 2:1.

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sudhir.kumar

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