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A block of mass 2 kg slides on a horizontal floor with velocity 4 m/s. It hits an uncompressed spring and compresses it till its final velocity reduces to zero the kinetic frictional force is 15 N and spring constant is 10000 N/m. Find the spring compression

Answers (1)

Change in Kinetic energy = Work done by all forces.

Here  \Delta K=W_{s}+W_{f}

Wf = Work done by spring 

Wf = Work done by friction

    \frac{1}{2}.2\times 2\times 4^{2}=15x+\frac{1}{2}\times 10,000\ x^{2}

\Rightarrow\ 16=5000x^{2}+15x

\Rightarrow\ 5000x^{2}+15x-16=0

On solving it x = 5.5 cm

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