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A solid mixture (10g) consisting of MgCO3 and Na2CO3 was heated until the mass of the residue was constant. If the loss in mass is 44%. Find the amount of MgCO3 and Na2CO3 in the mixture respectively.

 

Option: 1

8.4g, 1.6g


Option: 2

1.6g, 8.4g


Option: 3

5g, 5g


Option: 4

8.8g, 1.2g


Answers (1)

best_answer

The reactions occur as follows:

\mathrm{M g CO_{3} \stackrel{\Delta}{\longrightarrow} M g O+CO_{2}}

N a_{2}CO_{3} \stackrel{\Delta}{\longrightarrow} x

Mass is lost in the form CO2

Thus, weight of CO2 = 4.4g

Thus, moles of CO2 = 0.1 = moles of MgCO3

Therefore, mass of MgCO3 in the mixture = 8.4g

Thus, mass of Na2CO3 in the mixture = 1.6g

Therefore, Option(1) is correct.

Posted by

himanshu.meshram

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