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Q.33) An oxygen cylinder of volume 30 litre has 18.20 moles of oxygen. After some oxygen is withdrawn from the cylinder, its gauge pressure drops to 11 atmospheric pressure at temperature $27^{\circ} \mathrm{C}$. The mass of the oxygen withdrawn from the cylinder is nearly equal to:
[Given, $R=\frac{100}{12} J \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$, and molecular mass of $\mathrm{O}_2=32$, 1 atm pressure $\left.=1.01 \times 10^5 \mathrm{~N} / \mathrm{m}\right]$

A) 0.144 kg

B) 0.116 kg

C) 0.156 kg

D) 0.125 kg

 

Answers (1)

best_answer

From the question,

$PV = (n-x) RT$
$11 \times 1.01 \times 10^5 \times \frac{30}{1000} = (18.20 - x)\times \frac{100}{12} \times 300 $
$x = 4.868 \text{mol}$

$\text {mass }=x \times \text { molecular mass }=4.868 \times 32 \approx 0.156 \mathrm{~kg}$

Hence, the answer is the option 3.

Posted by

Saumya Singh

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