In the following pairs of halogen compounds, which would undergo an SN2 reaction faster?
1. CH3CH2 CH2Cl or (CH3)2CHCl
2. CH3CH2CH2 I or CH3CH2CH2Br
1. CH3CH2 CH2Cl (1° alkyl halide) and (CH3)2CHCl (2° alkyl halide)-
Primary (1°) alkyl halide – minimal steric hindrance, secondary (2°) alkyl halide – more steric hindrance due to extra methyl group.
Faster SN2 rate- CH3CH2 CH2 Cl (1° alkyl halide) due to less hindered (primary) systems.
2. CH3CH2CH2 I and CH3CH2CH2Br-
These are both primary alkyl halides having the same steric hindrance, then comparing leaving groups: I- > Br- in leaving ability.
Faster SN2 rate- CH3CH2CH2 I as iodide is a better leaving group than bromide.