Browse by Stream
QnA
Home

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Two rods of same length are arranged as shown. The ends are maintained at temperature 100∘c and 70∘c. The temperature at the junction point

Two rods of the same length but different thermal conductivities K1 ​ and  K2 ​ are joined end to end (in series) are arranged. The ends are maintained at temperatures of 100∘C and 70∘C. The temperature T at the junction point?

Answers (1)

best_answer

Given- 

  • Lengths of rods = same
  • Thermal conductivities: K1, K2 ?
  • One end of rod 1 = 100°C
  • One end of rod 2 = 70°C
  • The temperature at the junction = T

To find- T

Solution- In steady-state heat conduction, the rate of heat flow (Q) through both rods must be equal = K1A(100−T)L=K2A(T−70)L

As A and L are the same. So, K1(100−T)=K2(T−70) 100K1+70K2=T(K1+K2)  T=100K1+70K2(K1+K2)

Posted by

Saniya Khatri

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Bhavya Jha starts NEET prep in Class 11, cracks AIR 8 with self-study; Rajasthan toppers share prep strategies
anam-khan

CBI arrests 2 for deceiving NEET UG 2025 aspirants by posing as middlemen
anam-khan

NEET MBBS cut-off for EWS category; college-wise opening and closing ranks for AIQ seats

Latest Question