# Q. 13.     A circular flower bed is surrounded by a path $4\; m$ wide. The diameter of the flower bed is $66\; m$. What is the area of this path? $(\pi =3.14)$

It is given that the diameter of the flower bed is $66\; m$

Therefore, $r = \frac{66}{2} = 33 \ m$

Now, we know that

Area of the circle (A) = $\pi r^2$

$\Rightarrow \pi r^2= 3.14 \times(33)^2= 3419.46\ m^2$                             -(i)

Now, Area of outer circle with radius(r ') = 33 + 4 = 37 cm is

$\Rightarrow \pi r'^2= 3.14 \times(37)^2= 4298.66 \ m^2$                               -(ii)

Area of the path is equation (ii) - (i)

$\Rightarrow 4298.66-3419.46 = 879.2 \ m^2$

Therefore, the area of the path is  $879.2 \ m^2$

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