Q. 13.     A circular flower bed is surrounded by a path 4\; m wide. The diameter of the flower bed is 66\; m. What is the area of this path? (\pi =3.14)

               

Answers (1)

It is given that the diameter of the flower bed is 66\; m

Therefore, r = \frac{66}{2} = 33 \ m

Now, we know that

Area of the circle (A) = \pi r^2

\Rightarrow \pi r^2= 3.14 \times(33)^2= 3419.46\ m^2                             -(i)

Now, Area of outer circle with radius(r ') = 33 + 4 = 37 cm is 

\Rightarrow \pi r'^2= 3.14 \times(37)^2= 4298.66 \ m^2                               -(ii)                                       

Area of the path is equation (ii) - (i)

\Rightarrow 4298.66-3419.46 = 879.2 \ m^2

Therefore, the area of the path is  879.2 \ m^2

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