You must have heard these terms work, energy, and power very frequently in your day to day life, like a barber cutting hair, a laborer lifting bricks and transporting them and a student studying are all said to be working. But here in physics, work is defined using very specific words and it has a very precise meaning. Similarly, a gymnast who can do a lot number of pullups we say that he/she has very good stamina or in other words, he/she has a good amount of energy. This means energy is something which tells about the capacity to do the work. In physics as well energy is related to work similarly but as already mentioned the definition of the word Work is very precise itself in Physics hence the definition of energy as well. We often come across the word Power as well, for example, the bodybuilder hit the punching bag with huge power, so in a very crude way, we could say that the rate of doing work is power. We could loosely correlate the physical definitions and physiological pictures. In this chapter, we would go in depth of the definitions and relations between these three physical quantities.
Work is done by a force (Both constant force and a variable force), conservation of mechanical energy, potential energy, kinetic energy, workenergy theorem, Potential energy of a spring, conservative and nonconservative forces, power
This chapter is very important because it will test your knowledge of the previous two chapters namely, Kinematics, Laws of Motion and it will be also useful and crucial for you for solving questions from the next chapters namely System of Particles, Rotational Motion and to some extent gravitation.
Here we will try to understand the definition of Work, Energy, and Power.
Work: It is defined as the product of the force applied to the object and the distance it travels in the direction which is parallel to the direction of the force. It is represented by the letter W. It is a scalar quantity. S.I. unit of work is Nm or J (joules).
Energy: It is the capacity to do work, it has the same unit as work and also it is a scalar quantity. But energy exists in many forms like Kinetic energy, Potential energy, Thermal energy, Heat energy, etc, but here we will only talk about kinetic energy and potential energy. It is denoted by letter E.
Power: It is the rate of doing work or the rate of transferring energy, It is denoted by the letter P and its S.I. units are J/s or W (watts).
You will also come across a very important theorem of this chapter, known as a workenergy theorem. This theorem states that the work done on the particle due to all types of forces equals to change in kinetic energy of the particles. Let’s understand this theorem with the help of an example.
Example  A bobpendulum was hanging through a height ‘h’ from its equilibrium position as shown in the figure. How much velocity will it attain at its equilibrium position if it is dropped from the height ‘h’?
Solution  We will take the help of Work energy theorem for solving this problem. Assuming the mass of the bob is ‘m’. The force which is acting on the bob is a gravitational force due to its weight.
Its initial velocity is zero,
It is one of the basic and important chapters in mechanics because with the help of the concept used in this chapter you will be able to solve questions from other mechanics chapters as well. So for preparing this chapter, you need to remember the concept from laws of motion and you should be able to understand what kind of forces are acting on the particle. You should also understand how scalar product of the two vectors is operated and what is the significance of scalar product. Because work, energy, and power all are a scalar quantity.
This chapter is more of a concept based chapter there is very little to memorize, hence practice is the key here for getting a good hold on this chapter.
Some questions of this chapter will involve the use of calculus and Scalar product of vectors, hence keep your basics strong.
Give a significant number of mock tests and make note of your progress.
It would be easy for you to solve questions if you can imagine what all forces are acting on the object and how.
Make a list of questions which you were not able to solve in the first attempt or you took a long time solving them, after a week or two solve them again.
For this chapter, we would recommend you to first go through NCERT book and your Lab manual and solve questions from those chapters. Then you should solve questions from NCERT Exemplar book for a good hold on this chapter. If you want to test yourself for competitive exams, then you should read Understanding Physics by D.C. Pandey.
Chapters No. 
Chapters Name 
Chapter 1 

Chapter 2 

Chapter 3 

Chapter 5 

Chapter 6 

Chapter 7 

Chapter 8 

Chapter 9 

Chapter 10 

Chapter 11 

Chapter 12 

Chapter 13 

Chapter 14 

Chapter 15 

Chapter 16 

Chapter 17 

Chapter 18 

Chapter 19 

Chapter 20 

Chapter 21 
Overview of the chapter
To study this chapter efficiently first you have to understand all the definitions and terminologies, given the chapters and try to interpret them in a very logical way. You must be good at basic laws like the law of energy conservation and theorems like a workenergy theorem Because you might get conceptual questions based on these laws And theorems. You will get various reallife application based problems on the concept like a workenergy theorem, law of energy conservation, Collision, Power.
For example, let's have a look question which is based on reallife activities and was asked in jee main 2016 from this chapter.
Q A person who is trying to lose weight by burning his fats lifts a mass of 10 kg 1000 times up to a height of 1 m. And also assume that the potential energy lost each time he lowers the mass is dissipated. By considering the work done only when the weight is lifted up then tell How much fat will he use up? ( If Fat supplies 3.8× J of energy on burning 1 kg fat which is converted to mechanical energy with a 20% efficiency rate. )
To solve these questions you first find work done by the person in lifting the weight
Which is equal to W=mgh
Which is equal to E
Then find Total fat burn by dividing W by E
Which is equal to
First, you should have good command over the concepts of Work Power and Energy and you should also know how to apply them well at the time of the entrance exam or while solving questions. Entrance 360 will help you to understand each concept from this chapter since it provides you theory, questions with solutions and video lectures on each important concepts. For each concept practice enough problems so that you are through with the concept. Take mock test and practice previous year questions. Through practice, you will come to know how to approach a question. There are direct formulas that can be applied to certain questions.
To Solve Work Power Energy Problems
Books
For Work Power and Energy chapter concepts in NCERT is enough and practice questions which are asked in previous questions and you can follow other standard books available for JEE preparation like Concepts of Physics (H. C. Verma) and Understanding Physics by D. C. Pandey (Arihant Publications). You don't have to study the whole book to understand the concept from this chapter because Entrance 360 will provide you exact page number and line number of these books where you will get these concepts to read.
A block of mass 0.50 kg is moving with a speed of 2.00 ms^{1} on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is
Option 1)  Option 2) 
Option 3)  Option 4) 
A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times. Assume that the potential energy lost each time he lowers the mass is dissipated. How much fat will he use up considering the work done only when the weight is lifted up ? Fat supplies 3.8×10^{7 }J of energy per kg which is converted to mechanical energy with a 20% efficiency rate. Take g = 9.8 ms^{−2} :
Option 1)
2.45×10^{−3} kg 
Option 2)
6.45×10^{−3} kg 
Option 3)
9.89×10^{−3} kg 
Option 4)
12.89×10^{−3} kg

An athlete in the olympic games covers a distance of 100 m in 10 s. His kinetic energy can be estimated to be in the range
Option 1)  Option 2) 
Option 3)  Option 4) 