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  • If X^y. y^x =16 , then dy/dx at (2,2) , is

If X^y. y^x =16 , then dy/dx at (2,2) , is

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Solution:   We have ,    x^ycdot y^x=16

                   yln x +xln y=ln 16

              Diffrentiating w.r.t x , we get

          yfrac1x+(ln x)y_1+(fracxy)y_1+ln y=0

Rightarrow            (fracmathrmd ymathrmd x)_2,2=-1.

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Deependra Verma

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