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  • (a) Account for the following:     (i) Mn shows the highest oxidation state of +7 with oxygen but with fluorine it shows the highest oxidation state of +4.     (ii) Zirconium and Hafnium exhibit similar propertie

(a) Account for the following:

    (i) Mn shows the highest oxidation state of +7 with oxygen but with fluorine it shows the highest oxidation state of +4.

    (ii) Zirconium and Hafnium exhibit similar properties.

    (iii) Transition metal acts as catalysts.

(b) Complete the following equations:

    (i) 2MnO_{2}+4KOH +O_{2}\overset{\Delta }{\rightarrow}

    (ii) Cr_{2}O_{7}^{2-}+14H^{+}+6I^{-}\rightarrow

 

 

 

 
 
 
 
 

Answers (1)

(a)

(i) Mn shows the highest oxidation state of +7 with oxygen but with flourine it shows the highest oxidation state of +4 is because of the ability of oxygen to form multiple bonds with Mn (d\pi - p\pi) but fluorine cannot do so.

(ii) Zirconium and Hafnium exhibit similar properties since there is an overall decrease in atomic radii of elements in 5d because of imperfect shielding of f electrons which is unable to counter balance effect of increased nuclear charge.

(iii) Transition metals acts as catalysts due to their ability to show multiple oxidation state and due to their tendency to form complexes.

(b)

(i) 2MnO_{2}+4KOH +O_{2}\overset{\Delta }{\rightarrow} 2K_{2}MnO_{4}+2H_{2}O

(ii) Cr_{2}O_{7}^{2-}+14H^{+}+6I^{-}\rightarrow 2Cr^{3+}+3I_{2}+7H_{2}O

 

 

Posted by

Sumit Saini

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