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  • A faster train takes one hour less than a slower train for a journey of 200 km. If the speed of the slower train is 10 km/hr less than that of the faster train, find the speeds of two trains.   <div style="float:left; wi

A faster train takes one hour less than a slower train for a journey of 200 km.

If the speed of the slower train is 10 km/hr less than that of the faster train, find the speeds of two trains.

 

 
 
 
 
 

Answers (1)

Let the speed of fast train be X km/he 

speed of slower train = x - 10 km / hr 

According to the question fast train takes 1 hr less than slower one in covering 200 km 

\frac{200 }{x} = \frac{200}{x-10} - 1\\\\ \frac{200}{x} = \frac{200 - ( x-10)}{(x-10)} \\\\ 200 ( x-10) = 200 x - x ( x -10 )\\\\ 200 x - 2000 = 200 x - x ^2 + 10x \\\\ x ^ 2 - 10x -2000 = 0 \\\\ x ^2 -50 x + 40x -2000 = 0 \\\\ x (x-50 )+40 ( x-50 ) = 0

( x+40 )( x-50 ) = 0 \\\\ x = 50 , x = -40

Since X can't  be negative , so x = speed of faster train = 50 km /hr 

speed of slower train = 40 km /hr  

Posted by

Safeer PP

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