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A hemispherical tank full of water is emptied by a pipe at the rate of  3\frac{4}{7}  litres per second. How much time will it take to empty the tank, if it is 3 m in diameter ?  \left (\text{Take } \pi =\frac{22}{7} \right )

 

 

 

 
 
 
 
 

Answers (1)

\text{Tank diameter}= 3 \; m

\text{Radius}= \frac{3}{2} = 1.5 \; m

\text{Volume}= \frac{2}{3} \pi r^3

                  = \frac{2}{3} \times 3.14 \times (1.5)^3

                  = 7.605 \; m^3

\text{Volume} = 7605 \; l

\text{Emptying rate} = \frac{25}{7} \; \text{per second}

Let the time taken to empty half volume = t

\frac{25}{7} \times t = \frac{1}{2} \times \text{Volume}

t = \frac{1}{2} \times 7065 \times \frac{7}{25}

t = 989 \; \text{seconds}

 

Posted by

Ravindra Pindel

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