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(a)     Identify ‘A’ and ‘B’ in the following reaction:

        \xrightarrow {(\text{CH}_3\textup{CO})_2O} A \xrightarrow [\text{CH}_3\text{COOH}]{Br_2}B

(b)    Why does aniline not undergo Friedel-Crafts reaction?

 

 

 

 
 
 
 
 

Answers (1)

(a) 

 

(b)    Aniline does not undergo Friedel Crafts reactions due to salt formation between aniline and the catalyst anhydrous AlCl(Lewis Acid) as a result nitrogen acquired positive charge group for further reaction.

Posted by

Sumit Saini

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