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  • A wire is bent in the form of a square of side 27 cm .The wire is strengthened and bent into the form of a semi-circle.What will be the radius of the semi-circle so formed?

A wire is bent in the form of a square of side 27 cm .The wire is strengthened and bent into the form of a semi-circle.What will be the radius of the semi-circle so formed?

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Length of the wire=Perimeter of the square=27 imes4=108cm

When the wire is bent in the form of a semi-circle, then clearly the perimeter of the semi-circle would be 108cm.

Let r be the radius of the semi-circle.

Then, perimeter = r(pi+2)=r(frac227 +2)cm=frac36r7cm

herefore frac367r=108Rightarrow r=frac108 imes736cm=21cm

Hence the radius of the semi-circle is 21cm.

Posted by

Deependra Verma

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