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(a) Write the formula of the following coordination compound :

                Iron(III) hexacyanoferrate(II)

(b) What type of isomerism is exhibited by the complex[Co(NH_3 )5Cl]SO_{4} ?

(c) Write the hybridisation and number of unpaired electrons in the complex [CoF_{6} ]^{ 3-} . (Atomic No. of Co = 27)

 

 

 

 
 
 
 
 

Answers (1)

(a)

 Fe_{4}\left [ Fe(CN)_{6} \right ]_{3}

(b)

Ionization isomerism is shown by [Co(NH_3 )5Cl]SO_{4}.

(c)

 [CoF_{6} ]^{ 3-}

Co\left ( 27 \right )=

Co\left (3^{+} \right )=

\left [ Co \: F_{6} \right ]^{3^{-}}=

 

Hybridization sp^{3}d^{2}

Number of unpaired electrons = 4

Posted by

Sumit Saini

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