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An alloy contains 14% tin , 27% zinc and rest iron. Find the quantity of the iron in 1.2 kg of this alloy.

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Total quantity of the alloy = 1.2 kg= 1200 gram.

Percentage of iron in the alloy= [100-(14+27)]%=59%

	herefore Quantity of iron in 1.2 kg of the alloy =59% of 1200 gram 

	herefore (frac59100	imes1200)gram=708 , gram

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Deependra Verma

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