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An isosceles right angled current carrying loop PQR is placed in a uniform magnetic field \overrightarrow{B} pointing along PR. If the magnetic force acting on the arm PQ is F, then the magnetic force which acts on the arm QR will be
Option: 1 F
Option: 2 \frac{F}{\sqrt{2}}
Option: 3 \sqrt{2}F
Option: 4 -F

Answers (1)

The total force is zero for the loop. Force on PR=0 as PR is parallel to the magnetic field. So the force on QR should be -F

Option D -F is the right answer

Posted by

Safeer PP

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