An isosceles right angled current carrying loop PQR is placed in a uniform magnetic field pointing along PR. If the magnetic force acting on the arm PQ is F, then the magnetic force which acts on the arm QR will be
Option: 1 F
Option: 2
Option: 3
Option: 4 -F
The total force is zero for the loop. Force on PR=0 as PR is parallel to the magnetic field. So the force on QR should be -F
Option D -F is the right answer