Construct a with sides
and
. Then construct a triangle whose sides are
of the corresponding sides of
.
(i) Construct the required triangle ABC
(I) Draw a line BX which makes an acute angle with BC and is opposite of vertex A.
(iii) Cut four equal parts of line BX namely BB 1 , BB 2 , BB 3 , BB 4.
(iv) Now join B 3 to C. Draw a line B 4 C' parallel to B 3 C.
(vi) And then draw a line B'C' parallel to BC.
Hence AB'C' is the required triangle.