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  • Explain giving reasons for the following : (a) Photoelectric current in a photocell increases with the increase in the intensity of the incident radiation. (b) The stopping potential <img alt="(V_{0})" src="https://entrancecorner.co

Explain giving reasons for the following :

(a) Photoelectric current in a photocell increases with the increase in the intensity of the incident radiation.

(b) The stopping potential (V_{0}) varies linearly with the frequency (v) of the incident radiation for a given photosensitive surface with the slope remaining the same for different surfaces.

(c) Maximum kinetic energy of the photoelectrons is independent of the intensity of incident radiation.

 

 

 
 
 
 
 

Answers (1)

(a)    The number of photoelectrons emitted per second increases if the intensity is increased so photoelectric current increases.

(b)  eV_{0}=h\nu -h\nu _{0}

        V_{0}=\left ( \frac{h}{e} \right )\nu -\frac{h\nu _{0}}{e}

\Rightarrow V_{0}  vs  \nu is a straight line with a constant slope \frac{h}{e}

(c)  K_{max}=h\nu -h\nu _{0}

                =h\nu - \phi _{0}

\Rightarrow  The maximum kinetic energy of photoelectron is independent of the intensity of incident radiation.

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Safeer PP

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