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Find p(0),p(1) and p(2)for each of the following polynomials. p(y)=y^2-y+1​

Answers (1)

p(y)=y2-y+1​

p(0)=(0)2-0+1​ = 1

p(1)=(1)2-1+1​ = 1

p(2)=(2)2-2+1​ = 3

 

Posted by

Ravindra Pindel

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