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Find the coordinates of the focus axis of the parabola the equation of directrix and the length of the latus rectum for y^2=10x

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The;given;equation;is;y^2=10x\*Here;the;coefficient;of;x;is;positive.\* Hence,;the;parabola;opens;towards;the;right\*On;comparing;this;equation;with;y^2=4ax,;we;get,\*Rightarrow 4a=10Rightarrow a=frac52\*	herefore Coordinates;of;the;focus=(a,0)=(frac52,0)\* Axis;of;the;parabola;is;the;x-axis;i.e;y=0\*Equation;of;directrix; x=-a;i.e;x=-frac52\*Length;of;latus;rectum=4a=10

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Deependra Verma

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