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Find the domain of definition of f(x)=log (x+3) /x^2+3x+2 , where base 2

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Solution:  Here , \ f(x)= log_2(x+3)/x^2+3x+2=log_2(x+3)/(x+1)(x+2)

\ (x+3)> 0\ \Rightarrow x> -3

And denominator             (x+1)(x+2)
eq 0Rightarrow x
eq -1,-2

Domain=(-3,-infty )--1,-2

Posted by

Deependra Verma

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