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Find the minimum value of bcx+cay+abz , when xyz=abc

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Solution:   To find the minimum value of 

                                 bcx+cay+abz,

                  Write         xyz=abc

        Rightarrow            (bcx)(cay)(abz)=a^3b^3c^3=k

      Here ,   n=3

     Hence , minimum value of   bcx+cay+abz=n(k)^frac1n=3(a^3b^3c^3)^frac13=3abc.

      

Posted by

Deependra Verma

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