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  • Find the perimeter of the triangle with vertices (i) (0, 8), (6, 0) and origin ; (ii) (9, 3), (1, - 3) and origin.

Find the perimeter of the triangle with vertices (i) (0, 8), (6, 0) and origin ; (ii) (9, 3), (1, - 3) and origin.

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i)(0,8),;(6,0);and;(0,0)\*Distance;between;(0,8);and;(6,0)=sqrt(6-0)^2+(0-8)^2=sqrt64+36=sqrt100=10\*Distance;between;(6,0);and;(0,0)= sqrt(6-0)^2+(0-0)^2=sqrt36+0=sqrt36=6\*Distance;between;(0,0);and;(0,8)=sqrt(0-0)^2+(0-8)^2=sqrt0+64=sqrt64=8\* Perimeter=10+6+8=24;units\* \* ii)(9,3),;(1,-3);and;(0,0)\*Distance;between;(9,3);and;(1,-3)=sqrt(9-1)^2+(3-(-3))^2=sqrt64+36=sqrt100=10\* Distance;between;(1,-3);and;(0,0)=sqrt(1-0)^2+(-3-0)^2=sqrt1+9=sqrt10\* Distance;between;(0,0);and;(9,3)=sqrt(0-9)^2+(0-(-3))^2= sqrt81+9=sqrt90\* Perimeter=10+sqrt10+sqrt90=10+4sqrt10;units

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Deependra Verma

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