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Find the zeroes of the polynomial 4 root(3) x^2+5x -2 root(3)

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$4 \sqrt{3} x^2+5 x -2 \sqrt{3} =0\\ 4 \sqrt{3} x^2+8 x - 3x -2 \sqrt{3}=0 \\ 4x( \sqrt{3}x+2) - \sqrt{3}(\sqrt{3}x+2) =0 \\ (\sqrt{3}x+2)(4x-\sqrt{3})=0\\ x = \frac{-2}{\sqrt{3}} \ \ or \ x = \frac{\sqrt{3}}{4}$

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Ravindra Pindel

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