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  • If k,2k-1,2k+1 are three consecutive terms of an AP,find k?

If k,2k-1,2k+1 are three consecutive terms of an AP,find k?

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k,2k−1,2k+1 are three terms in A.P. Then,
Common difference between first two terms = 2k−1−k =k−1
Common difference between next two terms = 2k+1−2k+1 =2

The common difference between consecutive terms should be equal. 
Hence, k−1=2
k=3

Posted by

Deependra Verma

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