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If one of the zeros of the quadratic polynomial $x^{2}+3x+k$ is $2$ , then the value of $k$ is

$-10$

$-7$

$-2$

Answers (1)

Given one of the zeroes of $x^2+3x+k$ is 2

Therefore

$p(2)=0$

That is put the value of x=2 in the given polynomial

$\\p(2)=0\\implies\\2^2+3\times2+k=0\\4+6+k=0\\10+k=0 \\k=-10$

Posted by

Safeer PP

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