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If Square matrix A is such that 3A^3+2A^2+5A+I=0, Then A^-1 is equal to

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Solution:  We have ,

               Rightarrow     3A^3+2A^2+5A+I=0

                Rightarrow    A(3A^2+2A+5I)=-I

                    	herefore     A^-1=-(3A^2+2A+5I).  

                            ecause  Inverse of a matrix is unique

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Deependra Verma

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