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If the Integral of sinx/sin(x-a) =Ax+B In sin (x-a) +c, then A and B are given by

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Solution: 

          \Rightarrow I=int sinx/sin(x-a)hspace0.1cmdx

        Put          x-a=tRightarrow dx=dt

        \ Rightarrow I=int sin(t+a)/sint hspace0.1cmdt\ \Rightarrow I=int [sintcdot cosa+costcdot sina/sint]dt\ \Rightarrow I=tcdot cosa+(sina)ln sint+c\ \Rightarrow I=(x-a)(cosa)+(sina)ln sin(x-a)+c

Hence,     \Rightarrow A=cosa hspace0.2cm,B=sina

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Deependra Verma

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