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If the line x+2by+7=0 is a diameter of the circle x^2+y^2-6x+2y=0, then b=?

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Solution: Here the centre of the circle $(3,-1)$

Must lie on the line $\ x+2by+7=0$ .

Therefore , $3-2b+7=0Rightarrow b=5$

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Deependra Verma

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