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If y= tan^-1 3a^2x - x^3 / a( a^2-3x^2) show that dy/dx=?

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Solution:   We have ,

                 y=	an^-1frac3a^2x-x^3a(a^2-3x^2) ,  where   fracxa=	an 	heta

           Rightarrow         y=	an^-1[frac3	an 	heta-	an^3	heta 1-3	an^2	heta]=	an^-1(	an 3	heta)=3	heta=3	an^-1fracxa

         Hence ,                fracmathrmd ymathrmd x=frac3aa^2+x^2. 

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Deependra Verma

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