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In Figure-6, a tent is in the shape of a cylinder surmounted by a conical top. The cylindrical part is 2·1 m high and conical part has slant height 2·8 m. Both the parts have same radius 2 m. Find the area of the canvas used to make the tent. 

\left ( Use, \pi = \frac{22}{7}\right )

 

 

 
 
 
 
 

Answers (1)

\\\text { Area of canvas = Curved surface area of cone + curved surface area of cylinder } \\ =\pi rl + 2\pi r h \\ = \pi r (l + 2h ) \\\\ =\frac{22}{7} \times 2(2.8 + 2 \times 2.1) \\ =44 \mathrm{m}^{2}

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