Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • N identical drop of mercury is charged simultaneously to 10 volts. When combined to form one large drop the potential is found to be 40 volts, the value of N is

N identical drop of mercury is charged simultaneously to 10 volts. When combined to form one large drop the potential is found to be 40 volts, the value of N is

Answers (1)

The volume of bigger drop = NxVolume of the smaller drop. 

\\\frac{4}{3}\pi R^3=N\frac{4}{3}\pi r^3\\N=(\frac{R}{r})^3...........(1)

The charge is conserved. There fore

The capacity of bigger drop x potential = The capacity of smaller drop x potential

\\4\pi \epsilon_0R\times40=N\times4\pi \epsilon_0r\times10\\\Rightarrow \frac{R}{r}=\frac{N}{4}.........(2)

From (1) and (2)

\\(N)^{\frac{1}{3}}=\frac{N}{4}\\\\N=\frac{N^3}{64}\\N=8

Posted by

Safeer PP

View full answer

Similar Questions

Latest Question