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Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on Rs. 4000 for 2 years at 10% per annum. The sum placed on simple interest is:

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\ 	extPrinciple =operatornameRs 4000$  time $=2$ year  Rate $=10 \%$ \ Compound interest $= P 	imes(1+r)^n- P$ \ $I = P left( 1 + r )^ n - 1 
ight$ \ $I=4000(1+.10)^2-1$ \ $I =4000(1.21-1)$ \ $I =840$ \ AS per question, Simple interest $=840 / 2=420= PRT / 100$ \ $SO , I =420= P 	imes 0.08 	imes 3$ \ $I =1750 Rs$ \ Answer (C) $1750 Rs$

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Deependra Verma

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