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The area of triangle whose vertices are repersented by the complex number 0 ,z and ze^i(alpha) , equals

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Solution:  

             Delta =(i/4)eginvmatrix 0 &0 &1 \ z & arz &1 \ ze^(ialpha ) &arze^(-ialpha ) &1 endvmatrix=0

         Delta =(i/4)left | z 
ight |^2[e^-ialpha -e^ialpha ]=(1/2)left | z 
ight |^2sinalpha .

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Deependra Verma

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