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  • The equation of the transverse and conjugate axisof the hyperbola 16x² - y2 +64x + 4y +44 = 0 are(a) x = 2, Y + 2 =0 (b) x = 2, y = 2(c) y = 2 x + 2 = 0 (d) None of these?

The equation of the transverse and conjugate axisof the hyperbola 16x² - y2 +64x + 4y +44 = 0 are(a) x = 2, Y + 2 =0 (b) x = 2, y = 2(c) y = 2 x + 2 = 0 (d) None of these?

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16x^2-y^2+64x+4y+44=0\*Rightarrow 16x^2+64x-(y^2-4y)+44=0\* Rightarrow 16(x^2+4x+4-4)-(y^2-4y+4-4)+44=0\* Rightarrow 16(x+2)^2-64-(y-2)^2+4+44=0\* Rightarrow 16(x+2)^2-(y-2)^2-16=0\* Rightarrow (x+2)^2-frac(y-2)^216=1\* So,;transverse;axis;are;x+2=0;and;y-2=0\*

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Deependra Verma

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