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The general solution of the differential equation dy /dx =y tan x -y^2 sec x

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Solution:  We have ,

                 fracmathrmd ymathrmd x=y	an x-y^2sec x

         Rightarrow      frac1y^2fracmathrmd ymathrmd x-frac1y	an x=-sec x

           Putting       frac1y=vRightarrow -frac1y^2fracmathrmd ymathrmd x=fracmathrmd vmathrmd x.   We get

       Rightarrow       fracmathrmd vmathrmd x+	an xcdot v=sec x   Which is linear differential equation

               I.F=e^int 	an xdx=e^log sec x=sec x

      The solution is    vcdot sec x=int sec^2x dx+cRightarrow sec x =y(c+	an x).

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Deependra Verma

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