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The oxidation state of Ni in tetracarbonylnickel is​

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As we know that CO is a neutral ligand, its oxidation state in metal carbonyl is 0.

Since the overall charge on Ni(CO)4​ is 0, the oxidation state of Ni in Ni(CO)4​ will be 0.

Mathematically:-

In a complex sum of oxidation states of all the atoms is always equal to charge on the complex.

Let oxidation state of Ni be x.

As the oxidation state of CO is 0,

x+(4×0)=0

⇒x=0

Hence, the oxidation state of Ni in Ni(CO)4​ will be 0.

Posted by

Ankit Dutt

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