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The product of two successive integral multiples of 5 is 300. Then the numbers are:

Answers (1)

Assume the consecutive integral multiple of 5 be 5n and 5(n + 1) where n is a positive integer.

ATQ

5n x 5(n + 1) = 300

n2 + n – 12 = 0

(n – 3) (n + 4) = 0

n = 3 and n = – 4.

As n is a positive integer so n =3.

Hence the required numbers are 15 and 20.

Posted by

Ravindra Pindel

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