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The real part of complex number z= 2a+i\left ( 7-a \right ) when z becomes purely real will be  \left ( a\: \epsilon\: R \right )

 

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Given - $z = 2a + i(7 - a)$

For $z$ to be purely real, the imaginary part must be zero. So, we set the imaginary part equal to zero: $7 - a = 0$

Solving for $a$: $a = 7$

Now, substitute $a = 7$ into the real part of the complex number:
Real part of $z = 2a = 2 \times 7 = 14$

Thus, the real part of z when z becomes purely real is $14$

Posted by

Saniya Khatri

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