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  • There are 33 bags containing 33 colored balls Red, Green and Yellow.Bag 11 contains: 2424 green balls. Red balls are 44 more than blue balls. Proba

There are 33 bags containing 33 colored balls Red, Green and Yellow.Bag 11 contains: 2424 green balls. Red balls are 44 more than blue balls. Probability of selecting 11 red ball is 413413 
Bag 22 contains: Total balls are 88 more than 713713 of balls in bag 11. Probability of selecting 11 red ball is 1313. The ratio of green balls to blue balls is 1:21:2 
Bag 33 contains: Red balls equal total number of green and blue balls in bag 22. Green balls equal total number of green and red balls in bag 22. Probability of selecting 11 blue ball is 314314 
11 ball each is chosen from bag 11 and bag 22, What is the probability that 11 is red and other blue

Answers (1)

There are 3 bags containing 3 colored balls – Red, Green, and Yellow.

Bag 1 contains: 24 green balls. Red balls are 4 more than blue balls. The probability of selecting 1 red ball is 4/13 

Bag 2 contains: Total balls are 8 more than 7/13 of balls in bag 1. The probability of selecting 1 red ball is 1/3. The ratio of green balls to blue balls is 1:2 

Bag 3 contains: Red balls equal the total number of green and blue balls in bag 2. Green balls equal the total number of green and red balls in bag 2. The probability of selecting 1 blue ball is 3/14

find out: 1 ball each is chosen from bag 1 and bag 2, What is the probability that 1 is red and other blue?

solution:

let's take in bag 1 red balls are x, therefore, blue balls are x-4

probability of red

\\ \frac{x}{24+x+(x-4)}=\frac{4}{13}\ \\ \\ \Rightarrow x=16

so bag 1 contains green =24, red=16, blue=12

in bag 2 total balls = 8+ \frac{7}{13}\times 52 =36

green and blue balls are y and 2y, red balls are z

z+y+2y =36

\text{probability of red }= \frac{z}{36}=\frac{1}{3}\ \Rightarrow z=12

bag 2 contains red=12, green=8, blue=16

now the probability that one is red and the other is blue

\frac{16}{52}\times\frac{16}{36}+\frac{12}{52}\times\frac{12}{36}=\frac{25}{117}

 

Posted by

Ramraj Saini

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