Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Three consecutive natural number are such that the square of the middle number exceeds the difference of the square of the other two by 60. Find the numbers       

Three consecutive natural number are such that the square of the middle number exceeds the difference of the square of the other two by 60. Find the numbers 

 

 

 

 

 
 
 
 
 

Answers (1)

Let the 3 numbers are x , x+1 , x+2 

According to question 

(x+1)^2 = ( x+2)^2 - x^2 + 60 \\\\ x^2 + 1^2 + 2x = x^2 + 2^2 + 4x - x^2 + 60\\\\x^2 + 2x + 1 = 4 + 4x + 60 \\\\ x^2 + 2x + 1 - 4x - 64 = 0 \\\\ x^2 - 2x -63= 0\\\\ x ^2 - (9-7) x-63 = 0 \\\\ x^2 - 9 x + 7x - 63 = 0 \\\\ x (x-9)+ 7 (x-9) = 0

( x-9) ( x+7) = 0

x = 9    or x = -7  

since -7 is not natural no. , hence x = 9 

The natural numbers are 9,10,11

Posted by

Ravindra Pindel

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE Results 2024: Fake notice goes viral about Class 10th; official dates yet to be announced

Latest Question