Get Answers to all your Questions

header-bg qa

Using valence bond theory, predict the hybidization and magnetic character of the following:

(a) [NiCl_{4}]^{2-}

(b) [Co(C_{2}O_{4})_{3}]^{3-}

[At. no : Co=27, Ni=28]

 

 

 

 
 
 
 
 

Answers (1)

(a) [NiCl_{4}]^{2-}

The oxidation state of Ni in [NiCl_{4}]^{2-} is 2.

Electronic configuration of Ni^{2+}= [Ar]3d^{8}4s^{0}

 ground state

Cl- is a weak field ligand and hence form outer spin complex or high spin complex.

 

Hence it undergoes sp^{3} hybridisation. Since unpaired electrons are present, it shows paramagnetism.

(b) [Co(C_{2}O_{4})_{3}]^{3-}

Oxidation of Co is +3.

Electronic configuration of Co^{3+}=[Ar]3d^{6}4s^{0}

C_{2}O_{4}^{2-} is a weak field ligand and hence forms outer spin complex.

 excited state

Hence Co^{3+} shows d^{2}sp^{3} hybridisation and since there are unpaired electrons present, it exhibits paramagnetism.

 

 

Posted by

Sumit Saini

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads