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Using valence bond theroy predict the hybridization and magnetic character of the following:

(a) [CoF_{6}]^{3-}

(b) [Ni(CN)_{4}]^{2-}

 

 

 

 
 
 
 
 

Answers (1)

(a) [CoF_{6}]^{3-}

Oxidation number of Co is +3.

Electronic configuration of Co^{3+} = [Ar]3d^{6}4s^{0}

F- has a weak ligand and hence forms high spin complex.

Hence it undergoes d^{2}sp^{3} hybridization. Since there are unpaired electrons present it shows paramagentism.

(b) [Ni(CN)_{4}]^{2-}

Oxidation state of Ni in [Ni(CN)_{4}]^{2-} is +2.

Electronic configuration of Ni^{2+}=[Ar]3d^{8}4s^{0}

CN- is a strong field ligand and hence, it forms low soin complex.

 excited state

Hence, [Ni(CN)_{4}]^{2-} undergoes dsp^{2} hybridization. Since there is no unpaired electrons, it shows dimagnetism.

Posted by

Sumit Saini

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